THE LORD OF THE RINGS: TALES OF MIDDLE-EARTH

Saruman of Many Colors

Saruman of Many Colors

Saruman Multicolore


Creatura Leggendaria — Mago Avatar


Egida—Scarta una carta incantesimo, istantaneo o stregoneria. Ogniqualvolta lanci la tua seconda magia in ogni turno, ogni avversario macina due carte. Quando una o più carte vengono macinate in questo modo, esilia una carta incantesimo, istantaneo o stregoneria bersaglio con valore di mana pari o inferiore a quello di quella magia dal cimitero di un avversario. Copia la carta esiliata. Puoi lanciare la copia senza pagare il suo costo di mana.


5 / 4


Illustrated by Alexander Mokhov

· The Lord of the Rings: Tales of Middle-earth (LTR)


Saruman of Many Colors


#223 · Mythic · Italian · Nonfoil/Foil


Legal Formats

Standard
Pioneer
Modern
Legacy
Vintage
Commander
Oathbreaker
Alchemy
Explorer
Historic
Timeless
Brawl
Pauper
Penny

Variants

Under Construction

Prints


Rulings


2023-06-16 : If the spell you cast has {X} in its mana cost, you must choose 0 as the value of X when casting it without paying its mana cost.

2023-06-16 : If you cast a spell "without paying its mana cost," you can't pay any alternative costs. You can, however, pay additional costs, such as kicker costs. If the card has any mandatory additional costs, you must pay those.

2023-06-16 : If you don't have an enchantment, instant, or sorcery card in your hand, you won't be able to pay Saruman of Many Colors's ward cost.

2023-06-16 : If you don't want to cast the copy, you can choose not to; the copy ceases to exist the next time state-based actions are checked.

2023-06-16 : You cast the copy while the ability is resolving and still on the stack. You can't wait to cast it later in the turn.

2023-06-16 : You don't choose a target for Saruman of Many Colors's ability at the time it triggers. Rather, a second "reflexive" ability triggers when one or more cards are milled this way. You choose a target for that ability as it goes on the stack. Each player may respond to this triggered ability as normal.

Comments

Under Construction